The sides of a triangle are 12cm, 13cm and 5cm The radius of the inscribed is given as 6cm - Maths -

Question

The sides of a triangle are 12cm, 13cm and 5cm The radius of the
inscribed is given as 6cm What is its area?
How to do this sum? Please explain the formula with its
derivation

Priyanka Kedia · Accepted Answer

$I n Δ A B C, {A C}^{2} = {A B}^{2} + {B C}^{2} \Rightarrow {(13)}^{2} = {(12)}^{2} + {(5)}^{2} \Rightarrow 169 = 144 + 25 \Rightarrow 169 = 169 T h u s, Δ A B C i s a r i g h t t r i a n g l e . S o, A r e a o f Δ A B C = \frac{1}{2} \times A B \times B C = \frac{1}{2} \times 12 \times 5 = 30 {c m}^{2} A n d, A r e a o f i n s c r i b e d c i r c l e = π r^{2} = 3.14 \times 6^{2} = 113.04 {c m}^{2}$

The sides of a triangle are 12cm, 13cm and 5cm. The radius of the inscribed is given as 6cm. What is its area? How to do this sum? Please explain the formula with its derivation.

The sides of a triangle are 12cm, 13cm and 5cm. The radius of the inscribed is given as 6cm. What is its area?

How to do this sum? Please explain the formula with its derivation.