The rate of effusion of an unknown gas X at 480 K is 1.60 times, the rate of effusion of sulphur dioxide gas at 300 K. The molecular weight of X is

Dear Student,

 

The rate of effusion of a gas is inversely proportional  to the square root of the molecular mass `M` of the gas (to the square root of molecules mass `m`)
'R =C×1MSo from the data given, we have,1.6=RxRSO2=MSO2MxTherefore,Mx =MSO2(1.6)2=642.56=25 g/mol

Regards,

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