the probability of getting a number between 1 and 100 which is divisible by 7 is ___?
the first number b/w 1 and 100 divisible by 7 is 7
the last number b/w 1 and 100 divisible by7 is 98
an = a + ( n- 1) d
98 = 7 + 7n - 7
98 / 7= n
n= 14
favorable outcomes=14
probability=14/98
= 1/7
- -2
Smallest number divisible by seven = 7
Largest number divisible by seven = 98
Here a = 7 , d = 7 an = 9
an = a + (n-1)d
Substituting the value
98 = 7 + (n-1)7
98 - 7 = (n-1)7
91 = (n - 1)7
91/7 = (n-1)
(n-1) = 13
n = 14
Hence the number of favourable outcomes = 14
Total number of outcomes = 100
Probability of getting a number between 1 and 100 is 14/100 or 7/50
Hope its correct
- 0
well.. the ques itself says "between 1 & 100"
this simply implies that a number (n) which is
1<n<100.
where n is an integer(as per the ques.)
so total possible outcomes = 98
but the total possible outcomes would have been 100 only and only if the question said - "find the probability of getting a number divisible by 7 in first 100 natural numbers."
hope it helps..
cheers.. :)
- 9