The potential energy of a spring is 5J when stretched by 10cm. Calculate the additional work done to stretch by 10cm more.

Dear student,U1=12kx25=12k×0.102k=100.102=1000N/mU2=12×1000×0.20×0.20U2=20JAdditional work done=U2-U1=20-5=15JRegards

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