The potential energy of a spring is 5J when stretched by 10cm. Calculate the additional work done to stretch by 10cm more. Share with your friends Share 4 Decoder_2 answered this Dear student,U1=12kx25=12k×0.102k=100.102=1000N/mU2=12×1000×0.20×0.20U2=20JAdditional work done=U2-U1=20-5=15JRegards -3 View Full Answer