The potential energy of a particle of mass 1kg moving along x-axis given by U(x) =[x2/2-x] J.if total mechanical energy of a particle is 2J, find max speed.
speed is max when the potential energy is minimum = 0 ie: at x = 0 or at x = 2
2 J = p.e + k.e = 0 + k.e
=> with max speed v => k.e = 2
½mv² = 2
=> v = √4 = 2 m/s
2 J = p.e + k.e = 0 + k.e
=> with max speed v => k.e = 2
½mv² = 2
=> v = √4 = 2 m/s