the median of the data is 525. find x and y, if total frequency is 100
class 0-100 100-200 200-300 300-400 400-500 500-600 600-700 700-800 800-900 900-1000
frequeency 2 5 x 12 17 20 y 9 7 4
Class Interval Frequency Cumulative frequency
0-100 2 2
100-200 5 7
200-300 x 7+x
300-400 12 19+x
400-500 17 36+x
500-600 20 56+x
600-700 y 56+x+y
700-800 9 65+x+y
800-900 7 72+x+y
900-1000 4 76+x+y
Median = size of n/2th term
n/2 = 100/2 = 50
Let us assume that it lies in the class 300-400
⇒
⇒x=4
Hence our assumption is correct
Also 76+x+y =100
⇒ x+y =24
⇒ y = 20