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The magnitude of the earth's magnetic field at a place is B0 and the angle of dip is δ. A horizontal conductor of length ℓ lying along the magnetic north-south moves eastwards with a velocity v. The emf induced across the conductor is :-

(1) Zero

(2) B0ℓv sin δ

(3) B0ℓv

(4) B0ℓv cos δ

When the conductor is lying along the magnetic north - south moves eastward and it will cut vertical component of B

_{0}.

So the induced emf is ,

$e=v{B}_{vertical}l=v\left({B}_{0}\mathrm{sin}\delta \right)l={B}_{0}lv\mathrm{sin}\delta $

Regards

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