the inner and outer radii of a cylindrical pipe are 5 cm and

4cm respectively . find the area of cross section of the pipe.

since inner radius can't be greater than outer radius. so taking inner raddii as 4 cm and outer raddii as 5 cm
Inner radius of cylindrical pipe; r = 4 cm
Inner radius of cylindrical pipe; R = 5 cm
Since the cross-section of cylindrical pipe is circular.
So area of cross-section of pipe = πR2-r2 = 22752-42 = 227×9 = 28.285 cm2

  • 1

please answer me

  • -1

257.51 cm2

  • 2

314.16cm2

  • -1
What are you looking for?