The graph of the inequalities x=0,y=0,2x+y+6=0 is1. First quadrant 2.That half of xy plane which lies above the line 2x+y+6=0 Share with your friends Share 2 Anuradha Sharma answered this Although your question is not clear as inequality sign is missing, So assuming it as, x≥0, y≥0 , 2x+y+6≥0Now line 2x+y+6 =0 cut the x axis at -3, 0 and y axis at 0,-6So in the below figure green region is the region for 2x+y+6≥0and region above x axis is for y≥0 and region right side to the y axis is for x≥0Now int≥rsection of all these three will be First quadrant that is crossmarkes region. -5 View Full Answer
