the Fe in (Fe(H2O)5NO) SO4 has how 3 unpaired electrons !
why ...!?
The oxidation state of Fe in [Fe(H2O)5NO]SO4 is +1. Therefore
26Fe+1 = 1s2 2s2 2p6 3s2 3p6 4s1 3d6
When the weak field ligand H2O and strong field ligand NO attack the configuration changes as follows:
26Fe+1 = 1s2 2s2 2p6 3s2 3p6 3d7 4s° 4p° 4d°
The number of unpaired electron in 3d sub-shell is 3.