The question is very easy. Look at the information given, i mean tangent makes an angle of 60 degree with positive x axis so it means that at the slope of tangent at the point is tan(60)= root 3
y=root x
on differentiating-
dy/dx=1/(2root x)
dy/dx= slope = tan(60)= root 3
root 3 = 1 / ( 2 root x)
so we get x= 1/12
now you have a value of x. Put this in the equation of cure to get value of y
y= root 1/12 or
y=1/( 2 root 3)
now equation of tangent can be given by point slope form
root 3*[ x- (1/12)]= [y- (1/2 root 3)]
for better understanding please copy and then read