the edges of a triangular board are 6 cm , 8 cm , 10 cm . calculate the cost of painting in at the rate of 9 paise per cm2

Dear Student,
Here is the solution of your asked query:
Edges of triangular board are 6cm, 8cm and 10cm.a=6, b=8 and c=10So, semi-perimeter of triangular board;s = a+b+c2=6+8+102=12 cmThen, area of triangular board is given by;A=ss-as-bs-c   =1212-612-812-10   =12×6×4×2   =2×2×3×2×3×2×2×2   =2×2×2×3   =24So area of triangular board = 24cm2Rate of painting=9 paise/cm2So total cost of painting = 24×9=216 paise
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