the diagonals of a rhombus are 6cm ,8cm .find the lenght of a side of a rhombus .also , find its area
The diagonals in a Rhombus bisect each other.
So,
By Pythagoras theorem,
AB=BC=CD=DA=√(3^2+4^2=√25=5
Area = 1/2 * product of diagonals = 1/2 * 6 * 8 = 24 cm^2