the diagonals of a rhombus are 6cm ,8cm .find the lenght of a side of a rhombus .also , find its area

The diagonals in a Rhombus bisect each other.

So,

By Pythagoras theorem,

AB=BC=CD=DA=√(3^2+4^2=√25=5

Area = 1/2 * product of diagonals = 1/2 * 6 * 8 = 24 cm^2

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1/ 2 * 6 * 8 = 24 cm2

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1/ 2 * 6 * 8 = 24 cm2

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1/ 2 * 6 * 8 = 24 cm2

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1/ 2 * 6 * 8 = 24 cm2

  • 1

1/ 2 * 6 * 8 = 24 cm2

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1/ 2 * 6 * 8 = 24 cm2

  • 0

1/ 2 * 6 * 8 = 24 cm2

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