The diagonals a rectangle ABCD intersect at a point O. If angle COD =78 then find the value of angle OAB
IF COD IS 78 THEN AOB WILL ALSO BE 78 (VERTICALLY OPPOSITE ANGLES)
DIAGONALS OF A RECTANGLE ARE EQUAL AND BISECT EACH OTHER
SO OAB + AOB +OBA = 180
OAB + OBA =102
2OAB = 102 (OBA=OAB)
OAB = 51
DIAGONALS OF A RECTANGLE ARE EQUAL AND BISECT EACH OTHER
SO OAB + AOB +OBA = 180
OAB + OBA =102
2OAB = 102 (OBA=OAB)
OAB = 51