the diagonal of a square lies along the line 8x-15y=0 one vertex is (1,2). find equations to the side of square passing through it?

Let ABCD be the given square and the coordinates of the vertex D be (1, 2).We are required to find the equations of its sides DC and AD.Given that BD is along the line 8x – 15y = 0?y=, so its slope is [equation of straight line,y=mx+c,where m is slope]

The anglesmade by BD with sides AD and DC is 45° . Let the slope of DC be m. Then

Since AD and DC are perpendicular,therefore

Therefore, the equation of the side DC is given by

{equation of straight line, }

Similarly, the equation of another side AD is given by

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