The curves y2= 4a(x+2) (a 0) and x2+ y2 = 4 intersect each other in points A and B, then - Maths - Conic Sections

Question

The curves y2= 4a(x+2) (a>0) and x2+
y2 = 4 intersect each other in points A and B, then
value of 'a' [or which area of the region bounded by the parabola
and chord AB is maximum is given by

Amit Shukla · Accepted Answer

Kindly, refer to the below link for similar query,

https://www meritnation
com/cbse-class-12-science/math/math-part-ii/application-of-integrals/ncert-solutions/46_1_215_237_376_8042

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The curves y2= 4a(x+2) (a>0) and x2+ y2 = 4 intersect each other in points A and B, then value of 'a' [or which area of the region bounded by the parabola and chord AB is maximum is given by

The curves y²= 4a(x+2) (a>0) and x²+ y² = 4 intersect each other in points A and B, then value of 'a' [or which area of the region bounded by the parabola and chord AB is maximum is given by