Hello Fathima dear, here is the easy steps for one question posted by our friend sooriya.
Please pass this to our friend
Here it is
Hi sooriya, tan A + sin A = m and tan A - sin A = n
So m + n = 2 tan A
And m - n = 2 sin A
So m^2 - n^2 = (m + n)(m - n) = 4 tan A sin A
Now 4 √m n = 4 √ (tan^2 A - sin^2 A) = 4 sin A √ (1 - cos^2 A) /cos^2 A = 4 sin A (sin A/cos A) = 4 tan A sin A
Hence L H S = 4 tan A sin A = R H S [PROVED]