The base of an isosceles triangle is 4/3 cm. The perimeter of triangle is 4 2/15cm. what is the length of either of the remaining equal sides?

PERIMETER OF THE TRIANGLE= SUM OF THREE SIDES OF A TRIANGLE

ONE SIDE = 4/3CM  (GIVEN)

PERIMETER = 42/15CM(GIVEN)

HENCE PERIMETER - ONE SIDE OF THE TRIANGLE =LENGTH OF THE TWO SIDES OF THE TRIANGLE.

OR, 42/15 - 4/3 = 22/15

THEREFORE, LENGTH OF EACH OF THE REMAINING TWO SIDES = (22/15)/2 = 11/15

ANSWER = 11/15

Is it 42/15 or 4(2/15) i.e.62/15

Ok

Let The Other Side Be x cm Each.

Now Perimeter = 4 2/15 = 62/15 cm

Now Perimeter Of A Triangle = Sum Of All The Sides

=> 2x+4/3 = 62/15

=> 2x = 62/15-4/3

=> 2x = 42/15

=> x = 42/15*1/2 = 21/15 cm = 7/5 cm