The base of an isosceles triangle is 4/3 cm. The perimeter of triangle is 4 2/15cm. what is the length of either of the remaining equal sides? Share with your friends Share 11 Varun.Rawat answered this Kindly refer the following link : https://www.meritnation.com/ask-answer/question/the-base-of-an-isosceles-triangle-is-4-3cm-the-perimeter-of/linear-equations-in-one-variable/5173693 0 View Full Answer Tanya Aggarwal answered this PERIMETER OF THE TRIANGLE= SUM OF THREE SIDES OF A TRIANGLEONE SIDE = 4/3CM (GIVEN)PERIMETER = 42/15CM(GIVEN)HENCE PERIMETER - ONE SIDE OF THE TRIANGLE =LENGTH OF THE TWO SIDES OF THE TRIANGLE.OR, 42/15 - 4/3 = 22/15THEREFORE, LENGTH OF EACH OF THE REMAINING TWO SIDES = (22/15)/2 = 11/15ANSWER = 11/15 -4 Dhananjay answered this Is it 42/15 or 4(2/15) i.e.62/15 4 Prakhar Bindal answered this OkLet The Other Side Be x cm Each.Now Perimeter = 4 2/15 = 62/15 cmNow Perimeter Of A Triangle = Sum Of All The Sides=> 2x+4/3 = 62/15=> 2x = 62/15-4/3=> 2x = 42/15=> x = 42/15*1/2 = 21/15 cm = 7/5 cm 4 Megha Binu answered this let the equal sides be xperimeter=4 2/15=62/15 cmacoording to the question,x+x+4/3=62/15i.e. 2x+4/3=62/152x=62/15-4/3(lcm of 15 and 3=15 :. the fraction without the denominator as 15 will be changed)i.e. 4/3=20/152x=62/15-20/152x=42/15x=42/15*reciprocal of 2x=42/15*1/2x=14/5*1/2x=7/5 -4