THE ANGLES OF A TRIANGLE ARE IN A.P.THE GREATEST ANGLE IS TWICE THE LEAST.FIND ALL THE ANGLES OF THE TRIANGLE.

let the angles of the triangle which r in AP be a-d, a, a+d

by angle sum property of triangle,

a-d+a+a+d = 180

3a = 180

a = 60

by the given condition,

a+d = 2(a-d)

a+d = 2a-2d

-a = -3d

a = 3d

3d = 60

d = 20

Therefore the angles of the triangle are,

a-d = 60-20 = 40

a = 60

a+d = 60+20 = 80

the angles of the triangle are 40,60,80

hope this helps

thumbs up plzzz

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