Suresh buys lemons at 6 for a rupee and an equal number at 8 for a rupee.
If he mixes them together and sells the whole lot at 8 for a rupee. find his gain or loss percentage

Question

Suresh buys lemons at 6 for a rupee and an equal number at 8 for a
rupee
If he mixes them together and sells the whole lot at 8 for a rupee
find his gain or loss percentage

Varun.Rawat · Accepted Answer

Suppose Seema buys x number of lemons of both types
CP of 6 lemons of first type = Re 1CP of x lemons of first type = Rs x6CP of 8 lemons of second type = Re 1CP of x lemons of second type = Rsx8CP of x lemons of first type + CP of x lemons of second type = x6 + x8 = Rs7x24So, CP of 2x lemons = Rs 7x24SP of 8 lemons = Re 1SP of 2x lemons = Rs 18×2x = Rsx4CP > SP, so loss ocurrsnow, loss = CP - SP = 7x24 - x4 = Rsx24Loss % = lossCP×100% = x247x24×100% = 14
29%

Suresh buys lemons at 6 for a rupee and an equal number at 8 for a rupee. If he mixes them together and sells the whole lot at 8 for a rupee. find his gain or loss percentage

Suresh buys lemons at 6 for a rupee and an equal number at 8 for a rupee.
If he mixes them together and sells the whole lot at 8 for a rupee. find his gain or loss percentage