Supppose there are three compartments A(V=2L, P=1.5 atm) , B(V=4L,P=2.5 am),C(V=1L, P=1atm), each filled with inert gases.Calculate the total pressure if the barriers seprating the cpmpartments are removed .In this question why we cant find the total pressure just by adding the individual pressures given by daltons law.Ans is 2 atm. Please correct me where I am getting wrong

Dear Student,

Assuming temperature to be 298 KPAVA= nARTor, nA = PAVART           =(1.5)(2)(0.0821)(298)           =0.1226 molPBVB= nBRTor, nB = PBVBRT           =(2.5)(4)(0.0821)(298)           =0.4087 molPCVC= nCRTor, nC = PCVCRT           =(1)(1)(0.0821)(298)           =0.0408 molTotal moles, nT = nA+nB+nC                            =0.1226+0.4087+0.0408                            =0.5721 molVT=VA+VB+VC    =2+4+1    =7LSo, PT=nTRTVT           =0.4617×0.0821×2987           =1.992 atm  

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