summation from r = 1 to 9 : (((r + 3 )/2r) * 9Cr) = (alpha * (3/2)9) + - Maths - Inverse Trigonometric Functions

Question

summation from r = 1 to 9 : (((r + 3 )/2r) *
9Cr) = (alpha * (3/2)9) + beta ,
then find the value of alpha , beta and alpha + beta No links

Ravendra Singh · Accepted Answer

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summation from r = 1 to 9 : (((r + 3 )/2r) * 9Cr) = (alpha * (3/2)9) + beta , then find the value of alpha , beta and alpha + beta . No links