Sum of two natural numbers is 8.if the sum of their reciprocal is 8/5.find the numbers
Let one number be x.
So another number would be 8-x.
A.T.Q
1/x + 1/ (8-x) = 8/5
8-x + x = 8
x(8-x) 5
8 = 8
x(8-x) 5
1 = 1
x(8-x) 5
5 = 8x -x2
x2 - 8x +5 = 0
Solving it we get numbers
4+ root 11 and 4 - root11
So another number would be 8-x.
A.T.Q
1/x + 1/ (8-x) = 8/5
8-x + x = 8
x(8-x) 5
8 = 8
x(8-x) 5
1 = 1
x(8-x) 5
5 = 8x -x2
x2 - 8x +5 = 0
Solving it we get numbers
4+ root 11 and 4 - root11