Sum of two natural numbers is 8.if the sum of their reciprocal is 8/5.find the numbers

Let one number be x.
So another number would be 8-x.
A.T.Q
1/x + 1/ (8-x) = 8/5
8-x + x   8 
 x(8-x)        5  
    8      =   8 
 x(8-x)      5
    1      =   1 
 x(8-x)      5
5 = 8x -x2
x2 - 8x +5 = 0 
Solving it we get numbers
4+ root 11 and 4 - root11


 
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i think ur q is wrong
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Thank you nimish goyal
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