sum of the areas of two squares is 468 m2 . if the difference of their perimeter is 24 m . find the sides of the squares?

Dear Student!

The solution to your question is provided in the following link:

https://www.meritnation.com/ask-answer/question/sum-of-the-areas-of-two-squares-is-468-m2-if-the-differenc/quadratic-equations/478465

Hope you get this.

Cheers!

  • -2

Difference in perimeter is 4(a-b)=24  [a and b are sides of squares]

a-b=6;

a^2+(a-6)^2=468

a^2+a^2-12a+36=468

a^2-6a-432=0;

Solve the quadratic eqn to get the value of a and b

a=18

b=12

  • 18
What are you looking for?