sum of first p , q and r terms of an A.P. are a , b and c respectively. Prove that :
a/p (q-r) + b/p(r-p) + c/r (p-q) = 0
please make the correction, by the symmetry 2nd is b/q(r-p)
sum of first p , q and r terms of an A.P. are a , b and c respectively. Prove that :
a/p (q-r) + b/p(r-p) + c/r (p-q) = 0
let the first term of AP be A and common difference be d.
sum of the first p terms is
sum of the first q terms is
sum of the first r terms is
now
which is the required result.