Sulphur in vapour state exhibits paramagnetic behaviour, why? 

 In vapour state, Sulphur partly exists as S2 molecule, which has two unpaired electrons in antibinding pie orbitals, just like the O2 molecule. Hence, it exhibits paramagnetism.

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complete it p4+so2cl2

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Because in vapour state it exists as S2 molecule and has 2 unpaired electrons in antibonding pi orbital and hence exhibit paramagnetism.
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In vapour form, sulphur partly exists as S2 molecule which have two unpaired electrons in antibonding pie moleular orbital like oxygen, which makes them paramagnetic
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In vapour form, sulphur partly exists as S2 molecule which have two unpaired electrons in antibonding?pie moleular?orbital like oxygen, which makes them paramagnetic
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Initial amount of substance become 1/3 in 100 seconds. Calculate the time taken to reduce the concentration to 1/9 to the initial concentration.
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A reaction is50% complete in 2hrs and 75% complete BV in 4hrs what is order of reaction
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Sulfur exist as S8 molecule at ordinary temperature and pressure but at elevated temperature it gets dissociated and partly exists as S2 molecule in vapor phase. In this form S2 has 2 unpaired electrons in its anti bonding pi molecular orbitals and behave as a paramagnetic materials
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@Carrie_Bradshaw I think you mean pi. 
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above answer is correct
 
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In vapour state, Sulphur partly exists as S2
 
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Sulpher found as dimolecule in vapour phase and like dioxygen from MOT we can say disulpher has unpaired e- in molecular orbital.so it is paramagnetic.
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In vapour phase sulpher exhibits as S2 molecule as that of oxygen . As oxygen contains unpairede electrons 
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Because of 2 unpaired electrons
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Due to the presence of unpaired electrons
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nh3 has a greater affinity for protons than ph3?

 
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In vapour state sulphur exhibit paramagnetic behaviour this is because in vapour state the S2 molecules behave like O2 molecules .As we know that O2 has two unpaired electrons in the same way sulphur also have 2 unpaired electrons .and we know that an atom which has unpaired electrons acts as a paramagnetic(weakly repelled by the magnetic field) substance so sulphur exhibit paramagnetic behaviour in vapour state
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sulphur in vapour state exist as S2 and behave  like O2 has 2 unpaired electron in antibonding pi orbital responsible for paramagnetism 
 
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In vapour state, Sulphur partly exists as S2 molecule, which has two unpaired electrons in antibinding pie orbitals, just like the O2 molecule. Hence, it exhibits paramagnetism.
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sulphur in vapour form exhibits paramagnetic behaviour because in vapopur form sulphur exists as S2 molecule and has 2 unpairing electrons in pi antibonding orbital hence exhibiting  paramagnetic behaviour
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Sulphut exists as S8 molecule at ordinary temperature and pressure but at elevated temperature it gets dissociated and partly exists as S2 molecule in vapour phase. In this form S2 has 2 unpaired electrons in its anti bonding pi molecular orbitals and behave as a paramagnetic materials.
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cuz why not?
 
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Doesn't matter
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 In vapour state sulphur partly exists as S2 molecule and S2 molecule like O2 has two unpaired electrons in the anti bonding , orbital and hence exhibit paramagnetism.
 
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because in vapour state sulphur exist as S2molecule which is unpaired electron in the anti bonding orbital
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sulphur in Vapour state exist asS2 molecules which have a Two unpaired electron in the anti bonding orbital
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Because I dont know
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sulphur exhibit paramagnetic behaverior as it contain an empty antibonding pi orbital which is unpaired due to this behaviour its exisists only as paramagnetic and not as diamagnet
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The outermost configuration of sulphur is 3p^4 and therefore it has 2 unpaired electrons hence it shows paramagnetic behaviour...
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Because it exist in form of s8
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Sulpher exist in form of S8 but in vapour state it exhibit as S2
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In vapour sulphur exist as S2 and two unpaired electron of S2 molecule participate in anti bonding pi orbital so it shows paramagnetism
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Due to unpaired electron in antibonding orbitals.
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vapour?state?sulphur?partly exists as S2?molecule and S2?molecule like O2has two unpaired electrons in the anti bonding , orbital and hence?exhibit paramagnetism. ... It donates its electron pair and forms a linkage with metal ion.
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Because we know that O2 is paramagnetic. and sulphur has same outer electronic configuration as O2.
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In?vapour state,?Sulphur?partly exists as S2?molecule, which has two unpaired electrons in antibinding pie orbitals, just like the O2molecule. Hence, it exhibits paramagnetism.
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Sulphur exists as S2 molecule in Vapour State and it has 2 unpaired electronsin anti bonding orbital so it exhibits paramagnetism ....I mean it donates it's electron pair and forms a linkage with metal ion with which it is bond ..... Hope it helps!! ??
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Science 6 chapter 50 question answer
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Sulphur in vapour state behave as oxygen.. which is paramagnetic..
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rapsuudy is correct
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In?vapour state,?Sulphur?partly exists as S2?molecule, which has two unpaired electrons in antibinding pi orbitals, just like the O2?molecule. Hence, it?exhibits paramagnetic
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In?vapour state,?Sulphur?partly exists as S2?molecule, which has two unpaired electrons in antibinding pi orbitals, just like the O2?molecule. Hence, it?exhibits paramagnetism.
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In vapour state sulphur partly exist as S2 molecule which has 2 unpaired electrons in the antibonding pi*- orbitals like O2 and hence it exhibits paramagnetism.
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Hindi mein surface chemistry
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?In vapour state, Sulphur partly exists as S2?molecule, which has two unpaired electrons in antibinding pie orbitals, just like the O2?molecule. Hence, it exhibits paramagnetism
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In vapour phase sulphur exist as S2 molecule and like O2 molecule , O2 have 2 unpaired electron lies in anti bonding in energy level , so its exhibits paramagnetic behavior .
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In the vapour state sulphur partly exists as S2 molecules similar to O2 molecules. Just like oxygen, sulphur molecules also two unpaired electrons in the antibonding π* orbitals. Therefore, it exhibits paramagnetic character in the vapour state.
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Because it orbital is singlly filled with electron which make it behave as paramagnetic
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Because electron is singlly filled in orbital s of sulphur
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In vapour state sulphur partly exists as S2 molecule and S2molecule like O2 has two unpaired electrons in the anti bonding , orbital and hence exhibit paramagnetism. ... It donates its electron pair and forms a linkage with metal ion.
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Due to the presence of my paired elecrons sulphur exist paramagnetism
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Under ordinary conditions sulphur exists as S8?in solid state.?In vapour state sulphur partly exists as S2?molecule and S2?molecule has two unpaired electrons in the antibonding ?* orbitals. Hence, in vapour state sulphur exhibits paramagnetism.
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Under this condition sulphur exists as s8 in solid state. In vapour state sulphur partly exists as s2 molecules and s2 has two unpaired electrons in the antibonding pie orbital. Hence in vapour state exhibits paramagnetism.
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In?vapour state,?Sulphurpartly exists as S2molecule, which has two unpaired electrons in antibinding pie orbitals, just like the O2?molecule. Hence, itexhibits paramagnetism. Because invapour state?it exists as S2 molecule and has 2 unpaired electrons in antibonding pi orbital and henceexhibit paramagnetism.
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In?vapour state?sulphur partly exists as S2?molecule and S2?molecule has two unpaired electrons in the antibonding ?* orbitals. Hence, in?vapour state?sulphur exhibits?paramagnetism.
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In?vapour state,?sulphur?partly exists as S2 molecule and has two unpaired electrons like O2 in the antibonding ?-orbital. Hence,?exhibits paramagnetism
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Because of presence of unpaired electrons in its antibonding ?- orbital
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Ans 83
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Under ordinary conditions?sulphur?exists as S8?in solid?state. In?vapour state sulphur?partly exists as S2?molecule and S2?molecule has two unpaired electrons in the antibonding ?* orbitals. Hence, in?vapour state sulphur exhibits paramagnetism.
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In hindi

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?In vapour state, Sulphur partly exists as S2?molecule, which has two unpaired electrons in antibinding pie orbitals, just like the O2?molecule. Hence, it exhibits paramagnetism
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That's why
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Magnet
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