Solve x-y=3 and 4x-y=60 by substitution and find value of X and y

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Please find the answer:
x-y=3
=> x=3+y          (1)
4x-y=60           6+ (2)
Substituting the value of x in equation (2) we get 
4(3+y)=60
=>12+4y=60
=>4y=60-12
=>y= 48/4
=> y=12
Hence the value of y=12
All the best!!!
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There is a mistake I have mistakely written +6 
 
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From first equation x-y=3, We get x=3+y....[1]
Putting Value of [1] in second equation 4(3+y)-y = 60
We get, 12+4y- y = 60=> 12+ 3y =60=> 3y= 60-12=>3y= 48=> y= 16....[2]
Putting value of [2] in first equation, We get=>x-16=3=>x=3+16=>x=19
Therefore the value of x is 19 & value of y is 16.
Hence the solution is (19,16).
I hope this answer is helpful:)

 
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The answer of that q is 24 and 21 how
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    x - y = 3 
     = 4 x- y = 60 
    from equation 1    x = 3 + y
now putting the value  of x in equation 2
    4 (3 + y)  - y   = 60
12 +3 y = 60
   y  =   60 -12 / 3
  y =    16
no pu the value of y in equation 1
     x -  16 = 3
    x = 16 +3  = 19 
 so the value of x  =  19     and y  =  16
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