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Solve this: 23 SUN 018-4-23 19:50

Dear Student

NaCl has rock salt like structure as shown in picture below,


From the figure above we can say that edge of the unit cell ;
'a' = rCl- + 2rNa+ + rCl- = 2 rCl-+ 2rNa+ =2  rCl-+ rNa+ 
Thus, distance between anion and cation is : 
rCl-+ rNa+ =a2
ρ (density) =Z * MMNA * a3Z= 4MM = 127 g/molNA = 6.022 * 1023ρ = 5.85 gcm35.85  =4 * 127 6.022 * 1023 * a3  a3 = 4 * 127 6.022 * 1023 * 5.85 = 1.44 * 10-24 cm3a = 1.44 * 10-243 = 5.2 * 10-8 cmFrom the first equation derived,distance between anion and cation = a2 =5.2 * 10-82 = 2.62 * 10-8 cm

Regards
Now, for finding a;

 

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