Solve this:

Solve this: 20 wtl) ec-z . O-Q-+crr•G. 04

The solution is as follows:

Q1:

In ccp/fcc lattice:

      Number of lattice points = number of octahedral voids = 2 (number of tetrahedral voids)

Thus,

      Let O^2- = n

       Octahedral voids (Y)= $\frac{n}{3}$
      Tetrahedral voids(X) = $$\begin{gathered} \frac{2n}{6}=\frac{n}{3} \\ Thus, \\ X_{\frac{n}{3}}{Y}_{\frac{n}{3}}{O}_n \\ = XY{O}_3 \end{gathered}$$


This is the correct way to solve. For further queries please ask in separate thread.