Solve this:

The solution is as follows:




Number of atoms of B = $\frac{1}{8}\times 8+ \frac{1}{2}\times 6=1 + 3 = 4$

Number of atoms of A = 4 (tetrahedral voids)


When atoms along body centered are removed:

      Number of atoms of B = 4 - $\frac{1}{8}\times 2 = 3.75$
    Number of atoms of A = 4 - 2 = 2

The formula is A₂B_3.75