dear student Prn=n!(n-r)!Pnn=n!(n-n)!=n!0!=n!1=n!Pn-1n=n!(n-(n-1))!=n!1!=n!1=n!hencePnn=Pn-1n regards

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dear student

{}_{r}^{n}P = \frac{n!}{(n - r)!} {}_{n}^{n}P = \frac{n!}{(n - n)!} = \frac{n!}{0!} = \frac{n!}{1} = n! {}_{n - 1}^{n}P = \frac{n!}{(n - (n - 1))!} = \frac{n!}{1!} = \frac{n!}{1} = n! h e n c e {}_{n}^{n}P = {}_{n - 1}^{n}P

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