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We havefx=x+1x<4Casei When x>0, hence mod will open with positive sign.x+1x<4x2+1x<4x2+1<4xx2-4x+1<0x2-22-4+1<0x2-22-3<0x2-22-32<0x-2+3x-2-3<0x-2-3x-2+3<0x2-3,2+3Caseii When x<0, hence mod will open with negative sign.-x+1x<4Multiply both sides by -1x2+1x>-4As x<0, hence when we take x to other side, sign of inequality will change.x2+1<-4xx2+4x+1<0x+22-4+1<0x+22-32<0x+2+3x+2-3<0x--2-3x--2+3<0x-2-3,-2+3Taking union of two cases we getx2-3,2+3-2-3,-2+3

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