Solve this: Q15. Calculate the emf of the following cell at 25° C. Ag (s) Ag+ (10–3 M) || Cu2+ (10–1M) | Cu (s) [Given , ∆ E ° cell = + 0.46 V and log 10n = Share with your friends Share 0 Vartika Jain answered this Dear Student, At cathode : Cu2+ + 2e- → Cu(s)At anode : 2Ag+ +2e- →2Ag(s)So, overall reaction is 2Ag(s) + Cu2+ → 2Ag+ + Cu(s)Ecell = E°cell -0.0591nlog [Ag+]2[Cu2+] =0.46-0.05912log (10-3)2(10-1) =0.46-0.02955log (10-5) =0.46+0.14775 =0.60775 V 0 View Full Answer