Solve this:

Q. Consider a sphere of radius R having charge q uniformly distributed inside it. At what minimum distance from its surface the electric potential is half of the electric potential at its centre? 

1   R                     2   R 2 3   4 R 3             4   R 3

Dear Student

we know potential outside the sphere is V1 = kQ/x     where x is the distance from the center x>r

 and potential inside the sphere V1 = kQ/2r [3-x2/r2]

 for center put x=0  Vo = 3kQ/2r

condition given is V1 = Vo/2

                      kQ/x  = (3kQ/2r)/2


 distance from the surface is  =x-r

                                         = 4r/3 -r =r/3

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