Solve this:
Q.8. Solve :
$$\begin{gathered} \frac{1}{2\left(x+2y\right)}+\frac{5}{3\left(3x-2y\right)}=\frac{-3}{2} \\ \frac{5}{4\left(x+2y\right)}-\frac{3}{5\left(3x-2y\right)}=\frac{61}{60} \end{gathered}$$
$\left(x=\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$2$}\right., y=5/4\right)$