Dear Student, Current through series resister=voltage across series resisterresistance of series resister=9-6100= 03A (by ohms law)Current through load resistance =voltage across load resisterresistance of load resister=61000= 006ACurrent through zener diode = 03- 006= 024AAnd power being dissipated in zener diode =6× 024=144mW Regards

Solve this plzzz..

Solve this plzzz.. A Of V, (—6 V) is to maintain a ac.rrs a resistance RL (z a series resStance R, (—100 Q). If the e.m.f. of source is E 9 V). calculate the value of current resistance, bner and load resistance. What is the power dissipated in Zene dice?

Dear Student,

C u r r e n t t h r o u g h s e r i e s r e s i s t e r = \frac{v o l t a g e a c r o s s s e r i e s r e s i s t e r}{r e s i s \tan c e o f s e r i e s r e s i s t e r} = \frac{9 - 6}{100} = . 03 A (b y o h m s l a w) C u r r e n t t h r o u g h l o a d r e s i s \tan c e = \frac{v o l t a g e a c r o s s l o a d r e s i s t e r}{r e s i s \tan c e o f l o a d r e s i s t e r} = \frac{6}{1000} = . 006 A C u r r e n t t h r o u g h z e n e r d i o d e = . 03 - . 006 = . 024 A A n d p o w e r b e i n g d i s s i p a t e d i n z e n e r d i o d e = 6 \times . 024 = 144 m W

Regards

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Solve this plzzz.. Solve this plzzz.. A Of V, (—6 V) is to maintain a ac.rrs a resistance RL (z a series resStance R, (—100 Q). If the e.m.f. of source is E 9 V). calculate the value of current resistance, bner and load resistance. What is the power dissipated in Zene dice?

Solve this plzzz..

Solve this plzzz.. A Of V, (—6 V) is to maintain a ac.rrs a resistance RL (z a series resStance R, (—100 Q). If the e.m.f. of source is E 9 V). calculate the value of current resistance, bner and load resistance. What is the power dissipated in Zene dice?