Solve this :   How to solve this question related to chemical kinetics?

18 .   For   a   certain   reaction   the   rate   law   is   rate = k C 3 2 .   If   the   rate   of   the   reaction   is   0 . 020   mol   L - 1 s - 1   when   C = 1 . 0   M ,   what   is   the   rate   when   C = 0 . 60   M   ? a .   0 . 0093 mol   L - 1   s - 1                                                     b .   0 . 012   mol   L - 1   s - 1     c .   0 . 033 mol   L - 1   s - 1                                                         d .   0 . 040 mol   L - 1   s - 1


 

Dear Student,


rate = k [C]32I. r1=k[C1]32   or, 0.020=k(1)32           ...(i)II. r2=k[C2]32   or, r2=k(0.60)32            ...(ii)Dividing (i) and (ii)0.020r2=(10.60)32or, r2= 0.020×(0.60)32         =0.0093 molL-1s-1Hence, correct answer is (a)

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