Solve this : 28. A particle is thrown vertically upward, its velocity at half of the height is 10m/s, then maximum height attained by it is : (g = 10m/s2) (a) 8m                                       (b) 20m (c) 10m                                     (d) 16m

Dear Student,

In the present problem we use the conservation of energy.

We know,

Let the total height up to which particle raised is 'h'. Then the velocity acquired by it at the half of the height 'h/2' is v'=10m/s.

Energy at the starting point,

.....................(1)

In the middle at height 'h/2'

................(2)

At height 'h'

..................(3)
Comparing equation (2) and (3):

Regards

• 0
What are you looking for?