Solve this :

2 .   If   D 1 = ab 2 - ac 2 bc 2 a 2 b a 2 c - b 2 c ac - ab ab - bc bc - ac c - b a - c b - a   &   D 2 = 1 1 1 a b c bc ac ab ,   then   D 1 D 2   is   equal   to - ( a )   0                                       ( b )   D 1 2                                         ( c )   D 2 2                                         ( d )   D 2 3
 

Dear Student,
Please find below the solution to the asked query:

We know that Ac=An-1where n is order of square matrix A and Ac is matrix formed by co-factorof each element.Hence for 3×3 matrix, we getAc=A2NowD2=111abcbcacabNow D1=ab2-ac2bc2a2ba2c-b2cac-abab-bcbc-acc-ba-cb-a which is nothing but determinantformed by writing cofactor of reach element of D2=111abcbcacabHenceD1=D22

Hope this information will clear your doubts about this topic.

If you have any doubts just ask here on the ask and answer forum and our experts will try to help you out as soon as possible.
Regards

  • -1
If A is the amplitude of the wave coming from a line source at distance r, then
  • -1
What are you looking for?