Solve this:
Dear student,
Ecell = Ecathode - Eanode = 0.88-0.77 = 0.11.
ΔG0 = -nFE0 = -96500 x 0.11 = -10.615 kJ
ΔG0 = -RTlnK
Putting values we get K = 72.5.
Hope it helps
Regards
Ecell = Ecathode - Eanode = 0.88-0.77 = 0.11.
ΔG0 = -nFE0 = -96500 x 0.11 = -10.615 kJ
ΔG0 = -RTlnK
Putting values we get K = 72.5.
Hope it helps
Regards