# Solve ques 47,48 and 49 with explanation

$Given,\phantom{\rule{0ex}{0ex}}V=10V\phantom{\rule{0ex}{0ex}}I=500\times {10}^{-3}A\phantom{\rule{0ex}{0ex}}{R}_{1}=\frac{V}{I}=\frac{10}{500\times {10}^{-3}}=20\Omega \phantom{\rule{0ex}{0ex}}Again,\phantom{\rule{0ex}{0ex}}V=I\left({R}_{2}+{R}_{3}\right)\phantom{\rule{0ex}{0ex}}10+{R}_{3}=\frac{V}{I}=\frac{10}{500\times {10}^{-3}}=20\phantom{\rule{0ex}{0ex}}{R}_{3}=10\Omega \phantom{\rule{0ex}{0ex}}E=10Vastheinternalcircuitiszero\phantom{\rule{0ex}{0ex}}$

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