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Q. Find the area of a right-angled triangle with hypotenuse 25 cm and altitude 24 cm.

We have,hyopotenuse = 25 cm; altitude = 24 cmNow, base = ?Now, by Pythagoras theorem,hypotenuse2 = altitude2 + base2252 = 242 + base2625 = 576 + base2base2 = 49base = 7 cmNow, area = 12×base×altitude=12×7×24=84 cm2

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b= h2 - a= 252 - 24=625 -576 =49
b = 7
Area of triangle = 1/2 bh = 1/2*7*24 = 84 cm2
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