Solve Q.14

14.
  In the given figure, prove that :
 

(i)  AC is parallel to DE
(ii)  DB = FC Solve Q.14

In ABC and EFD,ABC = EFD   90° each       AC = DE   Given       AB = EF    GivenABC  EFD  RHSBC = DF  CPCTSubtracting BF from both sides, we getBC - BF = DF - BFFC = DB   

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