Solve Q.14 14. In the given figure, prove that : (i) AC is parallel to DE (ii) DB = FC Solve Q.14 Share with your friends Share 5 Varun Rawat answered this In ∆ABC and ∆EFD,∠ABC = ∠EFD 90° each AC = DE Given AB = EF Given⇒∆ABC ≅ ∆EFD RHS⇒BC = DF CPCTSubtracting BF from both sides, we getBC - BF = DF - BF⇒FC = DB 0 View Full Answer