Solve for x: 16x2-20(a+b)+(6a2+13ab+6b2)=0 Share with your friends Share 2 Lovina Kansal answered this Dear student we have,16x2-20a+bx+6a2+13ab+6b2=0⇒x=20a+b±20(a+b)2-4166a2+13ab+6b232⇒x=20a+b±400a2+400b2+800ab-384a2-832ab-384b232⇒x=20a+b±16a2-32ab+16b232⇒x=20a+b±4a2-2ab+b232⇒x=5a+b±a-b8⇒x=5a+b+a-b8 or x=5a+b-a-b8⇒x=6a+4b8 or x=4a+6b8⇒x=3a+2b4 or x=2a+3b4 Regards 2 View Full Answer Joshua answered this opps i forgot to put x after 20(a+b). So the equation should be 16x2-20(a+b)x+(6a2+13ab+6b2) = 0 -1 Ipsita answered this cannot understand the question -1 Aryan Gogulwar answered this s u c k my c o c k -1
