Solve for the equation cos (tan-1x) = sin(cot-13/4)

costan-1x=sincot-134...1As we know that sin θ= cos 90-θ so, sincot-134=cos π2-cot-134Now we know that tan-1x+cot-1x=π2 soπ2-cot-134=tan-134 putting this we get, sincot-134=cos π2-cot-134=costan-134 Now putting this value in equation 1, we getcostan-1x=costan-134 or tan-1x=tan-134or x = 34

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