solve differential equation sqrt 1+x²+y²+x²y² + xy dy/dx=0

There's square root in the expresiion.!!

 i am sorry i didnot see the sqrt

ok the solution then is 

√(1+x²)/x = ydy/√(1+y²)

integrating the above eqn we get

put 1 + x² =t and dx = dt/2x ie 

tdt / 2(t²-1) = 2√(1+y²)

ln(t² -1) / 2 + C = 2√(1+y) 

sqrt(1+x²)dx/x = sqrt(1+x²) - arctanh(sqrt(1+x²))

https://www.symbolab.com