# Solve 10 Q.10. Prove that the sum of the squares of the reciprocals of two perpendicular diameter of an ellipse is constant.

Dear student

$\phantom{\rule{0ex}{0ex}}Note:\phantom{\rule{0ex}{0ex}}{\mathrm{sin}}^{2}A+{\mathrm{cos}}^{2}A=1\phantom{\rule{0ex}{0ex}}\mathrm{cos}\left(90°+A\right)=-\mathrm{sin}A\phantom{\rule{0ex}{0ex}}\mathrm{sin}\left(90°+A\right)=\mathrm{cos}A$
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