Six years ago a father s age was 2 years more than 8 times the son s age that time - Maths - Pair of Linear Equations in Two Variables

Question

Six years ago a father’s age was 2 years more than 8 times
the son’s age that time After
10 years from now father will be 2 5 times as old as the son that
time Find
(i) Their present ages
(ii) After how many years from today, will the age of father be
twice the age
of his son that time?

Shobhit Mittal · Accepted Answer

let the present age of father and son be x and y
x-6=8y+2   1x+10=2
5y solve the two eqn and get the agesRegards

Six years ago a father’s age was 2 years more than 8 times the son’s age that time. After 10 years from now father will be 2.5 times as old as the son that time. Find (i) Their present ages (ii) After how many years from today, will the age of father be twice the age of his son that time?

Six years ago a father’s age was 2 years more than 8 times the son’s age that time. After
10 years from now father will be 2.5 times as old as the son that time. Find
(i) Their present ages
(ii) After how many years from today, will the age of father be twice the age
of his son that time?