sinx dy/dx +3y =cosx

sinx. dy/dx+3y = cosx
dy/dx + 3/sinx.y = cosx/sinx
dy/dx + 3cosecx.y =cotx
I.F= e int. 3cosec.dx
=e ^log| cosecx - cotx|^3
= cosecx - cotx
y.(cosecx -cotx) = int. cotx(cosecx - cotx)
= int. cotx.cosecx- int. cot^2xdx
= - cosecx - int(cosec^2x-1)dx
= - (cosecx - cotx) + x +1
y = -1 + (x+c)/(cosecx - cotx
  • -22
How did (cosecx - cotx)^3 become cosecx-cotx
  • 7
yeah , it's a mistake.

could u rewrite ur statement.
  • 4
Sinx dy/dx=cosx-3y
  • -8
Solve the following differential equation

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Answer

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dy/dx=3x-x+7/x-2y-3
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Q.n 9

  • 2
Solve
  • 2
Neeche samjh me aaya sahi se video bhej do
  • -3
Early

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Please solve this differential equation

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Sinx dy/dx+3y=cosx
  • 1
Shop differential equation DY by DX + 3 Y equal to cos x
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