sin-1 ( x . root (1-x) - root(x).root(1-x^2) )
pls answer , I have a test tomorrow :/
take x = sin a & rootx = sin b
then it will be
sin^-1 (sin a root (1- sin^2b) - sin b root (1-sin^2a) )
sin^-1 (sina cosb -sinb cos a)
sin^-1 (sin (a-b))
a - b
sin^-1x - sin^1rootx
then it will be
sin^-1 (sin a root (1- sin^2b) - sin b root (1-sin^2a) )
sin^-1 (sina cosb -sinb cos a)
sin^-1 (sin (a-b))
a - b
sin^-1x - sin^1rootx
